2023-11-03 18:42:37 -03:00
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/*
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* TODO:
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* The current solution is not optimal, as it's preferable to buy new nodes, even if upgrading is cheaper.
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* TODO:
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* It may be helpful to calculate the money per second of each node on average, (total mps / total nodes) and compare
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* it to the time it would take to purchase the next cheapest upgrade, and if the average mps is greater than the
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* negative mps of the upgrade cost, then buy a new node.
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* TODO:
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* Potential Ideas:
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* Find a way to calculate how much mps an individual upgrade would give, and compare it to the average mps of the node.
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* ns.hacknet.getNodeStats(0).production
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* If the upgrade mps is greater than the average mps, then buy the upgrade.
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* If the upgrade mps is less than the average mps, then buy a new node.
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*/
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enum Type {
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2023-11-03 21:57:09 -03:00
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newNode = "node", level = "level", ram = "ram", core = "code",
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2023-11-03 18:42:37 -03:00
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}
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export async function main(ns: NS) {
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let timeout: number = <number> ns.args[0]
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let nodes = ns.hacknet.numNodes()
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2023-11-03 20:17:24 -03:00
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// If there are no nodes, buy one
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if (nodes === 0) {
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ns.hacknet.purchaseNode()
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nodes = 1
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}
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2023-11-03 18:42:37 -03:00
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let costs: { type: Type, cost: number }[] = []
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while (true) {
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costs = []
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// Go through each node and get the cheapest upgrade
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for (let i = 0; i < nodes; i++) {
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costs.push(getCheapestCost(ns, i))
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}
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// Buy the cheapest upgrade from all nodes
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let cheapest = Math.min(...costs.map(c => c.cost))
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// Find the index of the cheapest cost in the list
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let index = costs.findIndex(c => c.cost === cheapest)
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// Wait to buy the cheapest upgrade
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try {
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await buy(ns, costs[index].type, costs[index].cost, index, timeout)
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} catch (e) {
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ns.tprint(e)
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ns.exit()
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}
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// Make sure that the number of nodes is up-to-date
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nodes = ns.hacknet.numNodes()
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}
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}
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/**
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* Wait until the player has enough money to buy something
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* @param ns Global NS object
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* @param money Amount of money to wait for
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* @param timeout=-1 Number of seconds to wait before timing out.
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* @throws Error if the timeout is reached
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* @note This function will wait forever by default
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*/
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async function waitUntilMoney(ns: NS, money: number, timeout: number = -1) {
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2023-11-03 21:57:09 -03:00
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while (ns.getServerMoneyAvailable("home") < money) {
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2023-11-03 18:42:37 -03:00
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await ns.sleep(1000)
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if (timeout == 0) {
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2023-11-03 21:57:09 -03:00
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throw new Error("Timed out waiting for money")
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2023-11-03 18:42:37 -03:00
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} else if (timeout > -1) {
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timeout--
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}
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}
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}
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async function buy(ns: NS, type: Type, cost: number, node: number, timeout: number) {
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await waitUntilMoney(ns, cost, timeout)
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switch (type) {
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case Type.newNode:
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ns.hacknet.purchaseNode()
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break
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case Type.level:
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ns.hacknet.upgradeLevel(node)
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break
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case Type.ram:
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ns.hacknet.upgradeRam(node)
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break
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case Type.core:
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ns.hacknet.upgradeCore(node)
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break
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}
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}
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function getCheapestCost(ns: NS, node: number) {
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let nodeCost = ns.hacknet.getPurchaseNodeCost()
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let levelCost = ns.hacknet.getLevelUpgradeCost(node)
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let ramCost = ns.hacknet.getRamUpgradeCost(node)
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let coreCost = ns.hacknet.getCoreUpgradeCost(node)
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let cheapest = Math.min(nodeCost, levelCost, ramCost, coreCost)
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switch (cheapest) {
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case nodeCost:
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return { type: Type.newNode, cost: nodeCost }
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case levelCost:
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return { type: Type.level, cost: levelCost }
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case ramCost:
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return { type: Type.ram, cost: ramCost }
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case coreCost:
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return { type: Type.core, cost: coreCost }
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}
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}
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