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+{
+ "cells": [
+  {
+   "cell_type": "code",
+   "outputs": [],
+   "source": [
+    "from automata.fa.dfa import DFA\n",
+    "\n",
+    "# DFA which matches all binary strings ending in an odd number of '1's\n",
+    "my_dfa = DFA(\n",
+    "\tstates={'q0', 'q1', 'q2'},\n",
+    "\tinput_symbols={'0', '1'},\n",
+    "\ttransitions={\n",
+    "\t\t'q0': {'0': 'q0', '1': 'q1'},\n",
+    "\t\t'q1': {'0': 'q0', '1': 'q2'},\n",
+    "\t\t'q2': {'0': 'q2', '1': 'q1'}\n",
+    "\t},\n",
+    "\tinitial_state='q0',\n",
+    "\tfinal_states={'q1'}\n",
+    ")\n",
+    "\n",
+    "my_dfa.show_diagram()\n"
+   ],
+   "metadata": {
+    "collapsed": false
+   },
+   "id": "ad7a031539dffdd7",
+   "execution_count": null
+  },
+  {
+   "cell_type": "markdown",
+   "source": [
+    "# Question 6\n",
+    "Let $S = \\{0,1\\}^*$ be the set of all strings of zero and ones, which includes the empty string $\\epsilon$.\n",
+    "Let $h : S \\rightarrow \\mathbb{Z}^*$ be the function defined by $h(x)$ equal the number of zeros in $x$ multiplied by the number of ones in $x$\n",
+    "For example, $h(00100011) = 5 \\times 3 = 15, and h(111) = 0 \\times 3 = 0$\n",
+    "\n",
+    "(a) Is $h$ one-to-one? No, because both strings $001$ and $110$ map to the same value, $2$\n",
+    "$2 \\times 1 = 2$ and $1 \\times 2 = 2$\n",
+    "\n",
+    "(b) Is $h$ onto? Yes, because you can find every non-negative integer by multiplying any number of ones by one zero $(1 \\times 1), (1 \\times 2), ...$\n",
+    "Let the number of zeros be exactly 1, and n be the number of ones, and m be any non-negative integer\n",
+    "$h(n) = m, 1n = m, n = m$ "
+   ],
+   "metadata": {
+    "collapsed": false
+   },
+   "id": "b67364155fcb1072"
+  },
+  {
+   "cell_type": "markdown",
+   "source": [
+    "# Question 8\n",
+    "(a)\n",
+    "This function is not one-to-one (111110, 1111100 are both 5)\n",
+    "This function is onto (10, 110, 1110, 11...0 is all non-negative integers)\n",
+    "\n",
+    "(b)\n",
+    "This function is not one-to-one (11111, 01111 are both 1)\n",
+    "This function is onto (All strings are mapped to, as you can simply pad any character with any 4 characters first)\n",
+    "\n",
+    "(c)\n",
+    "This function is not one-to-one (Quebec, Yukon both are 0)\n",
+    "This function is not onto (None of the provinces contain 3 or 5 a's"
+   ],
+   "metadata": {
+    "collapsed": false
+   },
+   "id": "ead9052998c5edf6"
+  },
+  {
+   "cell_type": "markdown",
+   "source": [
+    "# Question 9\n",
+    "Consider the relation $R$ defined on the set $\\mathbb{Z}$ as follows:\n",
+    "$$R = \\{(m,n) | m,n \\in \\mathbb{Z}, mn < 0\\}$$\n",
+    "\n",
+    "(a) Is the relation reflexive? No\n",
+    "For every integer $x$, $x \\times x = x^2$, and by the definition of squares, can never be less than zero\n",
+    "\n",
+    "(b) Is the relation symmetric? Yes\n",
+    "Let $x, y$ be a pair of integers in the relation and $z$ be the product of $x and y$, so $x \\times y = -z$\n",
+    "Since multiplication is commutative, the position of $x$ and $y$ do not matter, so $(x,y)$ and $(y,x)$ are in the relation\n",
+    "(Both $x \\times y$ and $y \\times x$ equal $-z$)\n",
+    "\n",
+    "(c) Is the relation transitive? No\n",
+    "Let $a = 1, b = -2, c = 3$\n",
+    "$1 \\times -2 = -2$ and $-2 \\times 3 = -6$, however $1 \\times 3 = 3$, which is $> 0$\n",
+    "$\\therefore$ this relation is not transitive\n",
+    "\n",
+    "(d) Is this an equivalence relation? No, because these three conditions are not met"
+   ],
+   "metadata": {
+    "collapsed": false
+   },
+   "id": "874c8dbcc345edad"
+  },
+  {
+   "cell_type": "markdown",
+   "source": [
+    "# Question 11\n",
+    "Consider the relation $R$ defined on the set $\\mathbb{Z}$ as follows:\n",
+    "$$\\forall m,n \\in \\mathbb{Z}, (m,n \\in R \\text{ if and only if } m + n = 2k \\text{ for some integer } k$$\n",
+    "\n",
+    "(a) Is this relation reflexive? Yes\n",
+    "For every integer $x$, $x + x = 2x$, therefore it is reflexive\n",
+    "\n",
+    "(b) Is this relation symmetric? Yes\n",
+    "Let $x, y$ be a pair of integers in the relation and $z$ be the sum of these integers, so $x + y = 2z$\n",
+    "Since addition is commutative, the position of $x$ and $y$ do not matter, so $(x,y) and $(y,x) are in the relation\n",
+    "(Both $x + y$ and $y + x$ equal $2z$)\n",
+    "\n",
+    "(c) Is this relation transitive? Yes\n",
+    "Let $(a,b)$ and $(b,c)$ be valid pairs of integers of the relation $R$\n",
+    "$a + b = 2n$, and $b + c = 2p$"
+   ],
+   "metadata": {
+    "collapsed": false
+   },
+   "id": "5fe823d05dd08b12"
+  }
+ ],
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+}