def is_word(word):
	counter = 0
	for l in word:
		if (counter % 2) == 0: #zero is vowel, one is constanant
			if l == 'a' or l == 'e' or l == 'i' or l == 'o' or l == 'u':
				counter = counter + 1
			else:
				return False
		else:
			if l == 'b' or l == 'k' or l == 'p' or l == 't' or l == 'z':
				counter = counter + 1
			else:
				return False	
	return True
	
def cycle(lst):
	while True:
		yield lst
		x = lst[0]
		lst = lst[1:]
		lst.append(x)
		
class Skippy:
	def __init__(self, lst, offset)
		self.lst = lst
		self.offset = offset
		self.counter = 0
		
	def __next__(self)
		if self.counter >  length(self.lst)
			self.counter = 0