Finish Lab 3

This commit is contained in:
Isaac Shoebottom 2023-10-04 18:07:09 -03:00
parent 7fc0b79b52
commit 9ba4c8ebc9
8 changed files with 217 additions and 6 deletions

View File

@ -0,0 +1,17 @@
/**To compile, don't forget to add -lpthread. Might not work without that */
#include<pthread.h>
#include<stdio.h>
void* run (void* arg){
printf("Hello from run\n");
return NULL;
}
int main(){
pthread_t thread; // variable to store the reference to the thread
pthread_create(&thread, NULL, &run, NULL);
printf("In main"); // This section will be executed in parallel
pthread_join(thread,NULL); // necessary for waiting for the thread to finish
printf("In main 2");
return 0;
}

View File

@ -0,0 +1,23 @@
#include<pthread.h>
#include<stdio.h>
#include<stdlib.h>
#include<unistd.h>
#include<time.h>
#include<sys/time.h>
void* run (void* arg){
printf("Hello from run\n");
return NULL;
}
int main(){
pthread_t thread;
pthread_create(&thread, NULL, &run, NULL);
// While the sleep() function will appear to provide synchronization,
// it is incorrect, and if used for this purposes instead of join
// or synchronization mechanism - the grade for the assignment will be
// reduced
sleep(2);
printf("Back in main");
return 0;
}

View File

@ -0,0 +1,24 @@
#include<pthread.h>
#include<stdio.h>
#include<stdlib.h>
#include<unistd.h>
#include<time.h>
#include<sys/time.h>
void* run (void* arg){
sleep(10-(int)arg);
printf("Hello from run\n");
}
int main(){
pthread_t thread[10];
int i = 0;
for (i = 0 ; i < 10; ++i)
pthread_create(&thread[i], NULL, &run,(void*)i);
// If you plan to use the results of all the threads, consider
// using join for all of the threads
for (i = 0 ; i < 10; ++i)
pthread_join(thread[i],NULL);
printf("In main");
}

View File

@ -0,0 +1,21 @@
#include<pthread.h>
#include<stdio.h>
void* run (void* arg){
int i = (int) arg;
printf("Hello from run, arg is %i\n",i);
}
int main(){
pthread_t thread[10];
int i = 0;
for (i = 0 ; i < 10; ++i)
pthread_create(&thread, NULL, &run,(void*)i);
// Notice how warnings are generated. This can be resolved by properly
// allocating space for the thread parameters.
// Note, that if you are using stack variable, the values might be corrupted
for (i = 0 ; i < 10; i++){
pthread_join(thread[i],NULL);
}
printf("In main");
}

View File

@ -0,0 +1,31 @@
#include<pthread.h>
#include<stdio.h>
#include <stdlib.h>
typedef struct thread_args{
char letter;
int id;
}Args;
void* run (void* arg){
Args* argg = (Args*) arg;
int i = argg->id;
printf("Hello from run %d\n", i);
return NULL;
}
int main(int argc, char** argv){
pthread_t thread[10];
int i = 0;
for (i = 0 ; i < 10; i++){
Args* argg = (Args*) (malloc(sizeof(Args)));
argg->letter = 'q';
argg->id = i;
pthread_create(&(thread[i]), NULL, &run,(void*)argg);
}
for (i = 0 ; i < 10; i++){
pthread_join(thread[i],NULL);
}
// Free the resources somewhere, for long running program. Or let the OS handle that
printf("In main");
return 0;
}

View File

@ -0,0 +1,19 @@
#include<pthread.h>
#include<stdio.h>
void* run (void* arg){
printf("Hello from run\n");
return NULL;
}
int main(){
pthread_t thread;
pthread_create(&thread, NULL, &run, NULL);
pthread_detach(thread);
// This command will make thread detached. This means the resources will be released
// upon the thread's completion - calling return
// However, detached threads cannot be joined, which means if you care about the result
// of the thread execution - you should not be using pthread_detach
printf("In main");
return 0;
}

View File

@ -1,8 +1,42 @@
#include<stdio.h>
#include<sys/time.h>
#include<stdlib.h>
#include<unistd.h>
#include<string.h>
/**
* Question 1: Run the program with the problem size of 1000 and 10 threads, what is the approximate speedup you are achieving?
*
* Answer 1: On my home machine single threading took 0.640239 seconds and multithreading took 0.194644 seconds.
* On the lab machine single threading took 0.697472 seconds and multithreading took 0.114415 seconds.
* This means that the my home machine is 3.29 times faster and the lab machine is 6.10 times faster.
*
* Question 2: Is there a problem size / number of threads combination that slows down the computation process? Why do you think it is happening?
*
* Answer 2: There is a problem with having too many threads for the number of hardware threads available. Increasing past this only
* increases the overhead of creating and managing the threads. This is because the threads are not running in parallel and are instead
* being switched between by the OS. At lower matrix sizes the cost of creating threads and managing them is greater than the cost of
* just doing the computation in a single thread, so any combination where threads > the number of hardware threads will be slower, and
* as the matrix size approaches 1, than the greater effect thread creation and management will have on the speed of the program.
*
* Question 3: What is the minimum size of the problem that benefits from creating an extra thread?
*
* Answer 3: The lowest size on my home machine that consistently benefited from an extra thread was 150, but this can change depending
* on the specifications of the machine.
*
* Question 4: Does using the threads always improve execution duration?
*
* Answer 4: No, as the number of threads increases past the number of hardware threads available the execution duration increases
* due to managing the threads, as well as low size matrices where the cost of creating and managing threads is greater than the
* cost of just doing the computation in a single thread.
*
* Question 5: Guesstimate and comment on the nature of growth of the speedup with the number of threads is it linear, exponential, are there any limits?
*
* Answer 5: The speedup is linear up to the number of hardware threads available, given a large enough matrix size.
* Given a matrix of size x, the speedup of using y threads is approximately x/y, up to the number of hardware threads available.
* After this the speedup will decrease as the number of threads increases, due to the overhead of creating and managing threads.
**/
#include <stdio.h>
#include <sys/time.h>
#include <time.h>
#include <stdlib.h>
#include <string.h>
#include <pthread.h>
#define MAXN 5
@ -82,6 +116,23 @@ void *multiply_matrices_threaded(void *threadParams) {
* threading capacity and parallelize the computation in such a
* way that a thread computes result per one or more rows
*/
ThreadParams *t = (ThreadParams *) threadParams;
int N = t->size;
int row = t->row_index;
int column = 0;
int temp_result = 0;
while (row < N) {
column = 0;
while (column < N) {
temp_result = 0;
for (int i = 0; i < t->size; i++) {
temp_result = temp_result + t->first_array[row][i] * t->second_array[i][column];
}
t->result[row][column] = temp_result;
column = column + 1;
}
row += t->max_threads;
}
}
int main(int argc, char **argv) {
@ -121,6 +172,22 @@ int main(int argc, char **argv) {
* Write your code to create and use max_threads here, such that the threaded_result
* is populated with the result of the computation.
*/
thr->result = threaded_result;
pthread_t threads[max_threads];
for (int i = 0; i < max_threads; i++) {
ThreadParams *params = (ThreadParams *) malloc(sizeof(ThreadParams));
params->first_array = array1;
params->second_array = array2;
params->result = threaded_result;
params->row_index = i;
params->size = size;
params->max_threads = max_threads;
pthread_create(&threads[i], NULL, &multiply_matrices_threaded, (void *) params);
}
for (int i = 0; i < max_threads; i++) {
pthread_join(threads[i], NULL);
}
gettimeofday(&end, NULL);
//The next line is inspired by https://linuxhint.com/gettimeofday_c_language/
microseconds = (end.tv_sec * 1000000 + end.tv_usec) - (begin.tv_sec * 1000000 + begin.tv_usec);
@ -129,7 +196,7 @@ int main(int argc, char **argv) {
if (check_if_matrices_differ(result, threaded_result, size) != 0) {
printf("Threaded result differ from single core computation, error\n");
exit(0);
exit(1);
}
return 0;
}

9
Lab3/try-for-error.sh Normal file
View File

@ -0,0 +1,9 @@
#!/bin/bash
cond=0
while [ $cond -eq 0 ]
do
./build/Lab3 10 10 &> output.txt
cond=$?
echo $cond
done