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STAT6473/HW2.Rmd
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---
title: "Assignment 2"
subtitle: "STAT3373"
author: "Isaac Shoebottom"
date: "Sept 25th, 2025"
output:
html_document:
df_print: paged
pdf_document: default
---
```{r}
library(tidyverse)
dd <- beaver2
```
# Question 1
mu_0 = mean temperature when activ = 0
mu_1 = mean temperature when activ = 1
$$ H_0 : \mu_0 = \mu_1, \space H_1 : \mu_0 \neq \mu_1 $$
```{r}
t.test(temp ~ activ, data = dd)
```
Reject H_0, accept H_1, we conclude that mean temperatures differ by activity level
Now manually:
```{r}
summary_stats <- dd %>%
group_by(activ) %>%
summarise(
n = n(),
mean_temp = mean(temp),
var_temp = var(temp)
)
summary_stats
```
Compute Standard Error and t stat
```{r}
x0 <- summary_stats$mean_temp[summary_stats$activ == 0]
x1 <- summary_stats$mean_temp[summary_stats$activ == 1]
s0 <- summary_stats$var_temp[summary_stats$activ == 0]
s1 <- summary_stats$var_temp[summary_stats$activ == 1]
n0 <- summary_stats$n[summary_stats$activ == 0]
n1 <- summary_stats$n[summary_stats$activ == 1]
SE <- sqrt(s0 / n0 + s1 / n1)
t_stat <- (x0 - x1) / SE
t_stat
```
Compute DF
```{r}
df <- (s0/n0 + s1/n1)^2 /
((s0/n0)^2/(n0-1) + (s1/n1)^2/(n1-1))
df
```
Compute p-value
```{r}
p_value <- 2 * pt(-abs(t_stat), df)
p_value
```
This p value also matches the conclusion that t.test reaches, reject H_0, accept H_1. We conclude that mean temperatures differ by activity level
# Question 2
```{r}
dd <- iris %>%
filter(Species %in% c("setosa", "versicolor"))
```
mu_0 = mean Sepal.Length for setosa
mu_1 = mean Sepal.Length for versicolor
$$ H_0 : \mu_0 = \mu_1, \space H_1 : \mu_0 \neq \mu_1 $$
```{r}
t.test(Sepal.Length ~ Species, data = dd)
```
p-value \< 0.05, reject H_0, accept H_1. This indicates a statistically significant difference in mean Sepal.Length between setosa and versicolor.