Add quiz 3 content, and quiz 3 practice

tests/Q3/prefix.py

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+def with_prefix(prefixes, words):
+	for prefix in prefixes:
+		lst = [word for word in words if word.startswith(prefix)]
+		yield lst

tests/Q3/test_prefix.py

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+from prefix import with_prefix
+
+words=["apple","baby","abba"]
+a_words=["apple", "abba"]
+def test_simple():
+    assert list(with_prefix(["a"],words)) == [a_words]
+def test_order():
+    assert list(with_prefix(["b","a"],words)) == [["baby"], a_words]
+def test_multi():
+    assert list(with_prefix(["bb","ab"],words)) == [[],["abba"]]
+
+# Commented out because the solution I am submitting is not using regex
+#def test_regex1():
+#    assert list(with_prefix(["[a-z]b"], words)) == [ ["abba"] ]
+#def test_regex2():
+#    assert list(with_prefix([".*a$"], words)) == [ ["abba"] ]
+
+def test_gen():
+    gen = with_prefix(["b"],words)
+    assert next(gen) == ["baby"]
+
+
+
+
+def test_gen2(): #Testing out of order prefixes, with generator syntax
+	gen = with_prefix(["b", "a"], words)
+	assert next(gen) == ["baby"]
+	assert next(gen) == ["apple", "abba"]
+
+def test_gen3(): #Testing out returning the same number of elements as words, out of order
+	gen = with_prefix(["bab", "abb", "app"], words)
+	assert next(gen) == ["baby"]
+	assert next(gen) == ["abba"]
+	assert next(gen) == ["apple"]
+
+
+words2 = ["aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa", "z"]
+def test_gen4(): #Testing a long word and one letter word
+	gen = with_prefix(["a", "z"], words2)
+	assert next(gen) == ["aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa"]
+	assert next(gen) == ["z"]

tests/practice/Q3/practice_questions.py

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+def is_word(word):
+	counter = 0
+	for l in word:
+		if (counter % 2) == 0: #zero is vowel, one is constanant
+			if l == 'a' or l == 'e' or l == 'i' or l == 'o' or l == 'u':
+				counter = counter + 1
+			else:
+				return False
+		else:
+			if l == 'b' or l == 'k' or l == 'p' or l == 't' or l == 'z':
+				counter = counter + 1
+			else:
+				return False	
+	return True
+	
+def cycle(lst):
+	while True:
+		yield lst
+		x = lst[0]
+		lst = lst[1:]
+		lst.append(x)
+		
+class Skippy:
+	def __init__(self, lst, offset)
+		self.lst = lst
+		self.offset = offset
+		self.counter = 0
+		
+	def __next__(self)
+		if self.counter >  length(self.lst)
+			self.counter = 0
+			

tests/practice/Q3/test_practice_questions.py

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+from practice_questions import is_word
+
+def test_match():
+    assert is_word("akataka") == True
+    assert is_word("ububu") == True
+    assert is_word("ikekezaza") == True
+
+def test_extra():
+    assert is_word("akatakaa") == False
+    assert is_word("uububu") == False
+
+def test_bad_letter():
+    assert is_word("yakataka") == False
+    assert is_word("akatakala") == False
+
+def test_consonant_start():
+    assert is_word("kakataka") == False
+    assert is_word("bububu") == False
+
+
+from practice_questions import cycle
+def test_small():
+    lst = [1,2,3]
+    g = cycle(lst)
+    assert next(g) == lst
+    assert next(g) == [2,3,1]
+    assert next(g) == [3,1,2]
+
+def test_big():
+    n = 5000
+    lst = list(range(n))
+    g = cycle(lst)
+    for j in range(n):
+        lst2 = next(g)
+    assert lst2[0] == n-1
+    lst3 = next(g)
+    assert lst3==lst